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6NaOH + SnCl4 → 4NaCl + Na2[Sn(OH)6] | Phương Trình Phản Ứng Hóa Học
NaOH | sodium hydroxide | solid + SnCl4 | tin(iv) chloride | solid = NaCl | sodium chloride | solid + Na2[Sn(OH)6] | Sodium hexahydroxostannate(IV) | solid | Temperature: temperature, Other Condition excess chlorine
Introduce
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Detailed information about the equation
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Detailed information on the reactants
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Detailed information about the products of the reaction
Information about NaCl (sodium chloride)
Information about Na2[Sn(OH)6] (Sodium hexahydroxostannate(IV))
Detailed information about the equation
Reaction conditions when applied NaOH + SnCl4
- Catalyst: not available
- Temperature: normal
- Pressure: normal
- Other conditions: not available
Reaction process NaOH + SnCl4
Process: updating...
Note: not available
The result of the reaction NaOH + SnCl4
The phenomenon: updating...
Detailed information on the reactants
Information about NaOH (sodium hydroxide)
Information about SnCl4 (tin(iv) chloride)
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Detailed information about the products of the reaction
Information about NaCl (sodium chloride)
- Atomic weight: 58.4428
- Color: kết tinh màu trắng hay không màu
- Status: Chất rắn
Information about Na2[Sn(OH)6] (Sodium hexahydroxostannate(IV))
Total rating:
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The equations for preparation NaOH
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
The equations for preparation SnCl4
Catalyst
normal
Temperature
normal
Pressure
normal
Other conditions
normal
Catalyst
normal
Temperature
room temperature
Pressure
normal
Other conditions
normal
→ 5 +
Catalyst
concentrated HCl
Temperature
19 - 56
Pressure
normal
Other conditions
normal
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